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Теориясы: 02 Екі таңбалы сандарды көбейту

Тапсырма

Сандарды көбейту:

  \(\displaystyle \times\)\(\displaystyle 7\)\(\displaystyle 2\)
 \(\displaystyle 3\)\(\displaystyle 6\)
\(\displaystyle +\) 
 
 

 

Шешім

1. \(\displaystyle 3\underline{6} \)санының бірліктерін (бұл \(\displaystyle 6\)саны) \(\displaystyle 72{\small }\)санына көбейтеміз:

 

\(\displaystyle 6\cdot 72=432{\small . }\)

 

  \(\displaystyle \times\)\(\displaystyle \bf 7\)\(\displaystyle \bf 2\)
 \(\displaystyle 3\)\(\displaystyle \bf 6\)
\(\displaystyle +\) \(\displaystyle \bf 4\)\(\displaystyle \bf 3\)\(\displaystyle \bf 2\)
\(\displaystyle ?\)\(\displaystyle ?\)\(\displaystyle ?\) 
 \(\displaystyle ?\)\(\displaystyle ?\)\(\displaystyle ?\)\(\displaystyle ?\)

 

2. \(\displaystyle \underline{3}6\)санының ондығын (бұл \(\displaystyle 3\)саны) \(\displaystyle 72{\small }\)санына көбейтеміз:

 

\(\displaystyle 3\cdot 72=216{\small . }\)

 

  \(\displaystyle \times\)\(\displaystyle \bf 7\)\(\displaystyle \bf 2\)
 \(\displaystyle \bf 3\)\(\displaystyle 6\)
\(\displaystyle +\) \(\displaystyle 4\)\(\displaystyle 3\)\(\displaystyle 2\)
\(\displaystyle \bf 2\)\(\displaystyle \bf 1\)\(\displaystyle \bf 6\) 
 \(\displaystyle ?\)\(\displaystyle ?\)\(\displaystyle ?\)\(\displaystyle ?\)

 

3. Сандарды қосамыз:

\(\displaystyle +\) \(\displaystyle 4\)\(\displaystyle 3\)\(\displaystyle 2\)
\(\displaystyle 2\)\(\displaystyle 1\)\(\displaystyle 6\)  
 \(\displaystyle 2\)\(\displaystyle 5\)\(\displaystyle 9\)\(\displaystyle 2\)

 

Нәтижесінде келесіні аламыз:

  \(\displaystyle \times\)\(\displaystyle 7\)\(\displaystyle 2\)
 \(\displaystyle 3\)\(\displaystyle 6\)
\(\displaystyle +\) \(\displaystyle 4\)\(\displaystyle 3\)\(\displaystyle 2\)
\(\displaystyle 2\)\(\displaystyle 1\)\(\displaystyle 6\) 
 \(\displaystyle 2\)\(\displaystyle 5\)\(\displaystyle 9\)\(\displaystyle 2\)

Жауабы: \(\displaystyle 2592{\small . }\)