Skip to main content

Теориясы: 02 Екі таңбалы сандарды көбейту

Тапсырма

Сандарды көбейту:

 \(\displaystyle \times\)\(\displaystyle 2\)\(\displaystyle 3\)
 \(\displaystyle 3\)\(\displaystyle 2\)
\(\displaystyle +\) 
 
 

 

Шешім

1. \(\displaystyle 3\underline{2} \)санының бірліктерін (бұл \(\displaystyle 2 \)саны ) \(\displaystyle 23 {\small : }\)санына көбейтеміз:

 

\(\displaystyle 2 \cdot 23=46 {\small . }\)

 

 \(\displaystyle \times\)\(\displaystyle \bf2\)\(\displaystyle \bf3\)
 \(\displaystyle 3\)\(\displaystyle \bf2\)
\(\displaystyle +\) \(\displaystyle \bf4\)\(\displaystyle \bf6\)
\(\displaystyle ?\)\(\displaystyle ?\)  
 \(\displaystyle ?\)\(\displaystyle ?\)\(\displaystyle ?\)

 

2.\(\displaystyle \underline{3}2 \)санының ондығын (бұл \(\displaystyle 3 \)саны ) \(\displaystyle 23 {\small }\)санына көбейтеміз:

 

\(\displaystyle 3 \cdot 23=69 {\small . } \)

 

 \(\displaystyle \times\)\(\displaystyle \bf2\)\(\displaystyle \bf3\)
 \(\displaystyle \bf3\)\(\displaystyle 2\)
\(\displaystyle +\) \(\displaystyle 4\)\(\displaystyle 6\)
\(\displaystyle \bf6\)\(\displaystyle \bf9\) 
 \(\displaystyle ?\)\(\displaystyle ?\)\(\displaystyle ?\)

 

3. Сандарды қосамыз:

\(\displaystyle +\) \(\displaystyle 4\)\(\displaystyle 6\)
\(\displaystyle 6\)\(\displaystyle 9\)  
 \(\displaystyle 7\)\(\displaystyle 3\)\(\displaystyle 6\)

 

Нәтижесінде келесіні аламыз:

 \(\displaystyle \times\)\(\displaystyle 2\)\(\displaystyle 3\)
 \(\displaystyle 3\)\(\displaystyle 2\)
\(\displaystyle +\) \(\displaystyle 4\)\(\displaystyle 6\)
\(\displaystyle 6\)\(\displaystyle 9\)  
 \(\displaystyle 7\)\(\displaystyle 3\)\(\displaystyle 6\)

Жауабы: \(\displaystyle 736 {\small . }\)